Iteration utilities

Iteration utilities

Stateful(itr)

There are several different ways to think about this iterator wrapper:

  1. It provides a mutable wrapper around an iterator and its iteration state.
  2. It turns an iterator-like abstraction into a Channel-like abstraction.
  3. It's an iterator that mutates to become its own rest iterator whenever an item is produced.

Stateful provides the regular iterator interface. Like other mutable iterators (e.g. Channel), if iteration is stopped early (e.g. by a break in a for loop), iteration can be resumed from the same spot by continuing to iterate over the same iterator object (in contrast, an immutable iterator would restart from the beginning).

Examples

julia> a = Iterators.Stateful("abcdef");

julia> isempty(a)
false

julia> popfirst!(a)
'a': ASCII/Unicode U+0061 (category Ll: Letter, lowercase)

julia> collect(Iterators.take(a, 3))
3-element Array{Char,1}:
 'b'
 'c'
 'd'

julia> collect(a)
2-element Array{Char,1}:
 'e'
 'f'
julia> a = Iterators.Stateful([1,1,1,2,3,4]);

julia> for x in a; x == 1 || break; end

julia> Base.peek(a)
3

julia> sum(a) # Sum the remaining elements
7
source
Base.Iterators.zipFunction.
zip(iters...)

For a set of iterable objects, return an iterable of tuples, where the ith tuple contains the ith component of each input iterable.

Examples

julia> a = 1:5
1:5

julia> b = ["e","d","b","c","a"]
5-element Array{String,1}:
 "e"
 "d"
 "b"
 "c"
 "a"

julia> c = zip(a,b)
Base.Iterators.Zip2{UnitRange{Int64},Array{String,1}}(1:5, ["e", "d", "b", "c", "a"])

julia> length(c)
5

julia> first(c)
(1, "e")
source
enumerate(iter)

An iterator that yields (i, x) where i is a counter starting at 1, and x is the ith value from the given iterator. It's useful when you need not only the values x over which you are iterating, but also the number of iterations so far. Note that i may not be valid for indexing iter; it's also possible that x != iter[i], if iter has indices that do not start at 1. See the enumerate(IndexLinear(), iter) method if you want to ensure that i is an index.

Examples

julia> a = ["a", "b", "c"];

julia> for (index, value) in enumerate(a)
           println("$index $value")
       end
1 a
2 b
3 c
source
Base.Iterators.restFunction.
rest(iter, state)

An iterator that yields the same elements as iter, but starting at the given state.

Examples

julia> collect(Iterators.rest([1,2,3,4], 2))
3-element Array{Int64,1}:
 2
 3
 4
source
countfrom(start=1, step=1)

An iterator that counts forever, starting at start and incrementing by step.

Examples

julia> for v in Iterators.countfrom(5, 2)
           v > 10 && break
           println(v)
       end
5
7
9
source
Base.Iterators.takeFunction.
take(iter, n)

An iterator that generates at most the first n elements of iter.

Examples

julia> a = 1:2:11
1:2:11

julia> collect(a)
6-element Array{Int64,1}:
  1
  3
  5
  7
  9
 11

julia> collect(Iterators.take(a,3))
3-element Array{Int64,1}:
 1
 3
 5
source
Base.Iterators.dropFunction.
drop(iter, n)

An iterator that generates all but the first n elements of iter.

Examples

julia> a = 1:2:11
1:2:11

julia> collect(a)
6-element Array{Int64,1}:
  1
  3
  5
  7
  9
 11

julia> collect(Iterators.drop(a,4))
2-element Array{Int64,1}:
  9
 11
source
Base.Iterators.cycleFunction.
cycle(iter)

An iterator that cycles through iter forever. If iter is empty, so is cycle(iter).

Examples

julia> for (i, v) in enumerate(Iterators.cycle("hello"))
           print(v)
           i > 10 && break
       end
hellohelloh
source
repeated(x[, n::Int])

An iterator that generates the value x forever. If n is specified, generates x that many times (equivalent to take(repeated(x), n)).

Examples

julia> a = Iterators.repeated([1 2], 4);

julia> collect(a)
4-element Array{Array{Int64,2},1}:
 [1 2]
 [1 2]
 [1 2]
 [1 2]
source
product(iters...)

Return an iterator over the product of several iterators. Each generated element is a tuple whose ith element comes from the ith argument iterator. The first iterator changes the fastest.

Examples

julia> collect(Iterators.product(1:2, 3:5))
2×3 Array{Tuple{Int64,Int64},2}:
 (1, 3)  (1, 4)  (1, 5)
 (2, 3)  (2, 4)  (2, 5)
source
flatten(iter)

Given an iterator that yields iterators, return an iterator that yields the elements of those iterators. Put differently, the elements of the argument iterator are concatenated.

Examples

julia> collect(Iterators.flatten((1:2, 8:9)))
4-element Array{Int64,1}:
 1
 2
 8
 9
source
partition(collection, n)

Iterate over a collection n elements at a time.

Examples

julia> collect(Iterators.partition([1,2,3,4,5], 2))
3-element Array{Array{Int64,1},1}:
 [1, 2]
 [3, 4]
 [5]
source
Base.Iterators.filterFunction.
Iterators.filter(flt, itr)

Given a predicate function flt and an iterable object itr, return an iterable object which upon iteration yields the elements x of itr that satisfy flt(x). The order of the original iterator is preserved.

This function is lazy; that is, it is guaranteed to return in $Θ(1)$ time and use $Θ(1)$ additional space, and flt will not be called by an invocation of filter. Calls to flt will be made when iterating over the returned iterable object. These calls are not cached and repeated calls will be made when reiterating.

See Base.filter for an eager implementation of filtering for arrays.

Examples

julia> f = Iterators.filter(isodd, [1, 2, 3, 4, 5])
Base.Iterators.Filter{typeof(isodd),Array{Int64,1}}(isodd, [1, 2, 3, 4, 5])

julia> foreach(println, f)
1
3
5
source
Iterators.reverse(itr)

Given an iterator itr, then reverse(itr) is an iterator over the same collection but in the reverse order.

This iterator is "lazy" in that it does not make a copy of the collection in order to reverse it; see Base.reverse for an eager implementation.

Not all iterator types T support reverse-order iteration. If T doesn't, then iterating over Iterators.reverse(itr::T) will throw a MethodError because of the missing iterate methods for Iterators.Reverse{T}. (To implement these methods, the original iterator itr::T can be obtained from r = Iterators.reverse(itr) by r.itr.)

Examples

julia> foreach(println, Iterators.reverse(1:5))
5
4
3
2
1
source